x^2/3-10x^1/3+24=0

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Solution for x^2/3-10x^1/3+24=0 equation: 


x in (-oo:+oo)

(x^2)/3-((10*x^1)/3)+24 = 0

(x^2)/3+(-10/3)*x+24 = 0

1/3*x^2-10/3*x+24 = 0

DELTA = (-10/3)^2-(1/3*4*24)

DELTA = -188/9

DELTA < 0

x belongs to the empty set

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